Mr. Matthew Hamilton - U6L6

What is the center and radius of a circle given by the equation x² + y² + 20x + 12y - 153 = 0?

h = (-c/2) = -20/2 = -10

k = (-d/2) = -12/2 = -6

r = √[-e+(c/2)²+(d/2)²] = √(153 + 100 + 36) = √289 = 17

The center of the circle is at (-10, -6), and the radius is 17 units.

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