What is the center and radius of a circle given by the equation x² + y² + 20x + 12y - 153 = 0?
What is the center and radius of a circle given by the equation x² + y² + 20x + 12y - 153 = 0?
h = (-c/2) = -20/2 = -10
h = (-c/2) = -20/2 = -10
k = (-d/2) = -12/2 = -6
k = (-d/2) = -12/2 = -6
r = √[-e+(c/2)²+(d/2)²] = √(153 + 100 + 36) = √289 = 17
r = √[-e+(c/2)²+(d/2)²] = √(153 + 100 + 36) = √289 = 17
The center of the circle is at (-10, -6), and the radius is 17 units.
The center of the circle is at (-10, -6), and the radius is 17 units.